How do you differentiate $u= 8/(3x^2)$ ?

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Answer 1 · 2015-04-15T22:47:42

$u = 8/(3x^2)$

could be written as

$u = 8/3 x^(-2)$

so

$(du)/(dx) = (-2)*8/3 x^(-3)$

$= - 16/(3x^3)$

Answer 2 · 2015-04-15T23:29:04

Apr 15, 2015

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How do you differentiate u= 8/(3x^2)u= 8/(3x^2)?