How do you differentiate $y= 12(x^2-7)^(1/3)$ ?

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Answer 1 · 2015-04-25T19:40:10

I would use the Chain Rule to deal with the $()^(1/3)$ :
$y'=12*1/3(x^2-7)^(1/3-1)*2x=8x(x^2-7)^(-2/3)$

How do you differentiate y= 12(x^2-7)^(1/3)y= 12(x^2-7)^(1/3)?