How do you differentiate $y=3cot(ntheta)$ ?

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Answer 1 · 2017-09-27T07:54:13

$(dy)/(d theta)=-3ncsc^2 ntheta$

we will need the chain rule

$(dy)/(d theta)=(dy)/(du)(du)/(d theta)$

$y=3cot(ntheta)$

$u=ntheta=>(du)/(d theta)=n$

$:.y=3cotu=>(dy)/(du)=-3csc^2u$

$:.(dy)/(d theta)=(dy)/(du)(du)/(d theta)$

gives

$(dy)/(d theta)=(-3csc^2u)xxn$

simplifying and substituting back

$(dy)/(d theta)=-3ncsc^2 ntheta$

How do you differentiate y=3cot(ntheta)y=3cot(ntheta)?