How do you differentiate $y=-5^(4x^3)$ ?

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Answer 1 · 2016-01-30T07:47:18

you have to use chain rule to differentiate this function. this is how you do it,

$(dy)/(dx)$
$=d/(dx)(-5^(4x^3))$

$=-d/(dx)(5^(4x^3))$

suppose, a=5 so,

$-d/(dx)(5^(4x^3))$

$=-5^(4x^3)ln5d/(dx)(4x^3)$ [as, $d/(dx)(a^x)=a^xlna$ ]

$=-5^(4x^3)ln5*4*3x^2$

$=-12*5^(4x^3)x^2ln5$

How do you differentiate y=-5^(4x^3)y=-5^(4x^3)?