Question

How do you differentiate `y=a^3+cos^3x`?

Answer 1

`dy/dx=-3cos^2xsinx`

Explanation:

`"differentiate using the "color(blue)"chain rule"`

`"given "y=f(g(x))" then"`

`dy/dx=f'(g(x))xxg'(x)larr" chain rule"`

`y=a^3+(cosx)^3`

`rArrdy/dx=0+3(cosx)^2xxd/dx(cosx)`

`color(white)(rArrdy/dx)=-3cos^2xsinx`