How do you differentiate $y= -cos^-1 (1/x^5)$ ?

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Answer 1 · 2016-05-06T16:17:15

$y'=-5/(x^6(sqrt(1-1/x^10))$

Use chain rule $f(g(x))'=f'(g(x))*g'(x)$ and derivative property $cos^-1 x=-1/sqrt(1-x^2)$

$y'=-[-1/sqrt(1-(1/x^5)^2) *(-5)/x^6]$

$y'=-5/(x^6(sqrt(1-1/x^10))$

How do you differentiate y= -cos^-1 (1/x^5)y= -cos^-1 (1/x^5)?