How do you differentiate y = cos^-1 (e^-t)? Calculus Differentiating Trigonometric Functions Differentiating Inverse Trigonometric Functions 1 Answer Joel Kindiak Aug 29, 2015 Differentiate implicitly. Explanation: y=cos^-1 (e^(–t)) cos y = e^(–t) Differentiating wrt t: –sin y dy/dt = –e^(–t) –sqrt(1-cos^2 y) dy/dt = –e^(–t) –sqrt(1-e^(–2t)) dy/dt = –e^(–t) dy/dt = e^(–t) / sqrt(1-e^(–2t)) Answer link Related questions What is the derivative of f(x)=sin^-1(x) ? What is the derivative of f(x)=cos^-1(x) ? What is the derivative of f(x)=tan^-1(x) ? What is the derivative of f(x)=sec^-1(x) ? What is the derivative of f(x)=csc^-1(x) ? What is the derivative of f(x)=cot^-1(x) ? What is the derivative of f(x)=(cos^-1(x))/x ? What is the derivative of f(x)=tan^-1(e^x) ? What is the derivative of f(x)=cos^-1(x^3) ? What is the derivative of f(x)=ln(sin^-1(x)) ? See all questions in Differentiating Inverse Trigonometric Functions Impact of this question 4745 views around the world You can reuse this answer Creative Commons License