How do you differentiate $y= (e^2x + 1)^3$ ?

Question

2075 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-08-13T13:47:28

Assuming that the function ought to be $y= (e^(2x) + 1)^3$ , use the chain rule twice.

$y= (e^(2x) + 1)^3$

$dy/dx= 3(e^(2x) + 1)^2 [d/dx(e^(2x) + 1)]$

$= 3(e^(2x) + 1)^2[e^(2x)d/dx(2x)]$

$= 3(e^(2x) + 1)^2e^(2x)2$

$= 6e^(2x)(e^(2x) + 1)^2$

How do you differentiate y= (e^2x + 1)^3y= (e^2x + 1)^3?