How do you differentiate $y=(e^(2x)+1)^3$ ?

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Answer 1 · 2016-12-10T06:52:05

You have to use the chain rule: $f(g(x))' = f'(g(x)) * g'(x)$

In this case $g(x) = e^(2x) + 1$ , so we have:

$g'(x) = 2 e^(2x)$ , again by the chain rule.

And $f'(e^(2x) + 1) = 3 (e^(2x) + 1)^2$ .

Putting it all together we have:

$3 (e^(2x) + 1)^2 * 2 e^(2x) = 6 (e^(2x) + 1)^2 * e^(2x)$

How do you differentiate y=(e^(2x)+1)^3y=(e^(2x)+1)^3?