How do you differentiate $y = e^{- 2 x + x^{2}}$ $y = e^(-2x + x^2)$ ?

Question

How do you differentiate $y = e^{- 2 x + x^{2}}$ $y = e^(-2x + x^2)$ ?

1 Answer

Impact of this question

4471 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-01-07T01:14:46

$\frac{d y}{d x} = e^{- 2 x + x^{2}} (- 2 + 2 x)$ $dy/dx = e^(-2x+x^2)(-2+2x)$

Explanation:

Using the chain rule, along with the derivatives $\frac{d}{d x} e^{x} = e^{x}$ $d/dxe^x=e^x$ and $\frac{d}{d x} x^{n} = n x^{n - 1}$ $d/dxx^n=nx^(n-1)$ , we have

$\frac{d y}{d x} = \frac{d}{d x} e^{- 2 x + x^{2}}$ $dy/dx = d/dxe^(-2x+x^2)$

$= e^{- 2 x + x^{2}} (\frac{d}{d x} (- 2 x + x^{2}))$ $=e^(-2x+x^2)(d/dx(-2x+x^2))$

$= e^{- 2 x + x^{2}} (- 2 + 2 x)$ $=e^(-2x+x^2)(-2+2x)$

Science

Math

Humanities

... and beyond

How do you differentiate $y = e^{- 2 x + x^{2}}$ $y = e^(-2x + x^2)$ ?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you differentiate y = e^(-2x + x^2)y=e−2x+x2y = e^(-2x + x^2)?

1 Answer

Explanation:

Related questions

Impact of this question

How do you differentiate $y = e^{- 2 x + x^{2}}$ $y = e^(-2x + x^2)$ ?