How do you differentiate $y=e^((lnx))^2$ ?

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Answer 1 · 2016-12-21T14:32:05

$y' = 2x$

"e" and the natural logarithms are inverses, so they equal $x$ when in the form $ln(e^x)$ or $e^(lnx)$ .

Thus, $y = x^2$

The derivative of this is obtained using the power rule.

$y'= 2x$

Hopefully this helps!

How do you differentiate y=e^((lnx))^2y=e^((lnx))^2?