How do you differentiate $y=e^(xcosx)$ ?

Question

12943 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-11-28T21:40:36

$y=e^(xcosx)$

Use the exponent rule for differentiating, and use the product rule.
$dy/dx=[(x)(-sinx)+(1)(cosx)]*(e^(xcosx))$

$dy/dx=(cosx-xsinx)(e^(xcosx))$

How do you differentiate y=e^(xcosx)y=e^(xcosx)?