How do you differentiate y = ln(x^(1/2))? Calculus Basic Differentiation Rules Chain Rule 1 Answer Jim H Apr 1, 2015 y=ln(x^(1/2)) = 1/2 ln(x) (dy)/(dx)=1/2 d/(dx)(ln(x))=1/2*1/x=1/(2x) Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of y= 6cos(x^2) ? How do you find the derivative of y=6 cos(x^3+3) ? How do you find the derivative of y=e^(x^2) ? How do you find the derivative of y=ln(sin(x)) ? How do you find the derivative of y=ln(e^x+3) ? How do you find the derivative of y=tan(5x) ? How do you find the derivative of y= (4x-x^2)^10 ? How do you find the derivative of y= (x^2+3x+5)^(1/4) ? How do you find the derivative of y= ((1+x)/(1-x))^3 ? See all questions in Chain Rule Impact of this question 7920 views around the world You can reuse this answer Creative Commons License