How do you differentiate y = (sec x) (tan x)?
1 Answer
Feb 6, 2016
Explanation:
Use the product rule:
y'=tanxd/dx(secx)+secxd/dx(tanx)
You should know the identities:
d/dx(secx)=tanxsecx d/dx(tanx)=sec^2x
Which gives...
y'=tanx(tanxsecx)+secx(sec^2x)
Simplified:
y'=tan^2xsecx+sec^3x