How do you differentiate $y=((x+1)/(x-1))^2$ ?

Question

3361 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-05-16T01:04:12

I would use the Chain and Quotient Rule:
$y'=2((x+1)/(x-1))((x-1)-(x+1))/(x-1)^2=$
$=2((x+1)/(x-1))(-2)/(x-1)^2=$
$=-4(x+1)/(x-1)^3$

How do you differentiate y=((x+1)/(x-1))^2y=((x+1)/(x-1))^2?