How do you differentiate $y = x^5 + (7 − x)^5$ ?

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Answer 1 · 2018-04-13T09:18:34

$dy/dx = 5(x^4-(7-x)^4)$

$y = x^5+(7-x)^5$

$dy/dx= 5x^4 + 5(7-x)^4 * d/dx(7-x)$

$= 5x^4+5(7-x)^4 * (0-1)$

$= 5(x^4-(7-x)^4)$

How do you differentiate y = x^5 + (7 − x)^5y = x^5 + (7 − x)^5?