How do you differentiate $y=xe^(-kx)$ ?

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Answer 1 · 2017-01-23T12:23:21

$= e^(-kx) ( 1 - kx)$

$(xe^(-kx))^prime = (x)^prime e^(-kx) + x (e^(-kx))^prime$

$= e^(-kx) + x (-k)e^(-kx)$

$= e^(-kx) ( 1 - kx)$

How do you differentiate y=xe^(-kx)y=xe^(-kx)?