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How do you divide ${(\frac{2}{7})}^{- 3}$ $(2/7)^-3$ ?

1 Answer

Aug 1, 2015

${(\frac{2}{7})}^{- 3} = \frac{147}{8} = 18 \frac{3}{8}$ $(2/7)^(-3) = 147/8 = 18 3/8$

Explanation:

${(\frac{2}{7})}^{- 3}$ $(2/7)^-3$
$XXXX$ $color(white)("XXXX")$ $= \frac{1}{{(\frac{2}{7})}^{3}}$ $= 1/((2/7)^3)$

$XXXX$ $color(white)("XXXX")$ $= \frac{1}{\frac{2^{3}}{7^{3}}}$ $= 1/(2^3/7^3)$

$XXXX$ $color(white)("XXXX")$ $= \frac{7^{3}}{2^{3}}$ $= (7^3)/(2^3)$

$XXXX$ $color(white)("XXXX")$ $= \frac{147}{8}$ $= 147/8$

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