How do you divide $2a^4b^3diva^2b$ ?

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Answer 1 · 2015-04-11T11:45:24

$2a^4b^3diva^2b$

$= (2a^4b^3)/(a^2*b)$

To make the calculations easier, we group the same coefficients together.

$= 2(a^4/a^2)*((b^3)/b)$

In general, $color(blue)(a^m/a^n = a^(m-n)$

$= 2*a^(4-2)*b^(3-1)$

$color(green)( = 2*a^2*b^2$

Answer 2 · 2015-04-11T11:49:18

$2a^4b^3diva^2b$
or
$(2a^4b^3)/(a^2b)$
can be written as
$2/1 * a^4/a^2 * b^3/b$

using the principle that $x^m/x^n = x^(m-n)$

this can be written as
$2 * a^2 * b^2$
or just

$2a^2b^2$

How do you divide 2a^4b^3diva^2b2a^4b^3diva^2b?