How do you divide (3x^2 y^7 z^3) /(4x^3 y^-2 z)?

1 Answer
Alan P.
Jul 10, 2015

(3x^2y^7z^3)/(4x^3y^(-2)z) = (3y^9z^2)/(4x)

Explanation:

(3x^2y^7z^3)/(4x^3y^(-2)z)

color(white)("XXXX")= (3/4) * ((x^2)/(x^3)) * ((y^7)/(y^(-2))) * (z^3/z)

color(white)("XXXX")=(3/4) * (1/x) * (y^9/1) * (z^2/1)

color(white)("XXXX")= (3y^9z^2)/(4x)

Related questions
See all questions in Exponential Properties Involving Quotients
Impact of this question
1833 views around the world
You can reuse this answer
Creative Commons License