How do you divide $(49a^3bc^14)/(-7abc^8)$ ?

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Answer 1 · 2015-07-09T13:52:18

For clearness, you may want to split this up, and take the parts piece by piece.

$=49/-7*a^3/a*b/b*c^14/c^8$

$49/-7=-7$

$a^3/a=a^(3-1)=a^2$

$b/b=1$ (so it disappears later)

$c^14/c^8=c^(14-8)=c^6$

Now put it all together again:

$=-7*a^2*1*c^6=-7a^2c^6$

How do you divide (49a^3bc^14)/(-7abc^8)(49a^3bc^14)/(-7abc^8)?