How do you divide $(81r^10s^6)/((3r^2s)^4)$ ?

Question

1673 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-07-22T15:47:14

$=color(blue)(r^2s^2$

$(81r^10s^6)/(3r^2s)^color(blue)(4$

$=(81r^10s^6)/(3^color(blue)(4 ) r^(2*color(blue)(4)) s^color(blue)(4$

$=(cancel81r^10s^6)/(cancel81 r ^8s^4$

$=(r^10s^6)/(r^8s^4)$

Applying this property to the exponents of $r and s$ :

$=r^((10-8)) . s^((6-4))$

$=color(blue)(r^2s^2$

How do you divide (81r^10s^6)/((3r^2s)^4)(81r^10s^6)/((3r^2s)^4)?