Question

How do you divide `((b^4)/(b^7))^-5`?

Answer 1

I found: `b^15`

Explanation:

You can start inside the bracket by remembering that: `a^b/a^c=a^(b-c)`;
so you get:
`(b^(4-7))^-5=`
`=(b^-3)^-5=`
Now you can use the fact that `(a^b)^c=a^(b*c)`;
so you get:
`b^(-3*-5)=b^15`