How do you evaluate $48^(4/3)8^(2/3)(1/6^2)^(3/2)$ ?

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Answer 1 · 2016-05-02T05:49:22

$48^(4/3)* 8^(2/3)*(1/6^2)^(3/2)=2^(13/3)/3^(1/3)$

$48^(4/3)* 8^(2/3)*(1/6^2)^(3/2)$

= $(2xx2xx2xx2xx3)^(4/3)* (2xx2xx2)^(2/3)*((2xx3)^(-2))^(3/2)$

= $(2^4xx3)^(4/3)* (2^3)^(2/3)*(2xx3)^(-2xx3/2)$

= $2^(4xx4/3)*3^(4/3)*2^(3*2/3)*(2xx3)^(-3)$

= $2^(16/3)* 3^(4/3)* 2^2*2^(-3)*3^(-3)$

= $2^(16/3+2-3)xx3^(4/3-3)$

= $2^(13/3)xx3^(-1/3)$

= $2^(13/3)/3^(1/3)$

How do you evaluate 48^(4/3)*8^(2/3)*(1/6^2)^(3/2) 48^(4/3)*8^(2/3)*(1/6^2)^(3/2) ?