How do you evaluate #6*(11-6)-:2#?

Question

2229 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-09-12T15:11:19

#15#

#6xxcolor(red)((11-6))div2# is all one term, but work out the bracket first.

#6xx5div2 " "# which can also be written as #(6xx5)/2#

= # 30div2 =15#

OR

# 3xx5 = 15#

OR

#6 xx 2 1/2 = 15#