How do you evaluate 9-15div3(-3)^2+229−15÷3(−3)2+22?

1 Answer
Olivier B.
Jun 7, 2015

Operations in a calculation have priority rules:

powers > multiplications/divisions > additions/subtractions

rarr 9-15/3(-3)^2+22→9−153(−3)2+22 should be solved like this:

9-15/3(-3)^2+22 = 9-15/3*9+229−153(−3)2+22=9−153⋅9+22
= 9-5*9+22=9−5⋅9+22
= 9-45+22=9−45+22
= -36+22=−36+22
= -14=−14

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