How do you evaluate ((9 - 2)^2 + 4) + 4^2((9−2)2+4)+42?

1 Answer
Gió
Jun 11, 2015

You can use the sequence of priority normally called PEMDAS,

Explanation:

![http://www.coolmath.com/prealgebra/05-order-of-operations/05-order-of-operations-parenthesis-PEMDAS-01](useruploads.socratic.org)
I would start from the brackets and the squares:
((9-2)^2+4)+4^2=((9−2)2+4)+42=
((7)^2+4)+16=((7)2+4)+16=
=(49+4)+16==(49+4)+16=
Now I solve all the sums and subtractions:
=53+16=69=53+16=69

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