How do you evaluate $\int (- \frac{1}{3 x}) d x$ $int (-1/(3x)) dx$ for [1/11, 1/5]?

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How do you evaluate $\int (- \frac{1}{3 x}) d x$ $int (-1/(3x)) dx$ for [1/11, 1/5]?

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Answer 1 · 2015-10-19T09:59:50

$0, 26282$ $0,26282$

Explanation:

$\int_{\frac{1}{11}}^{\frac{1}{5}} - \frac{1}{3 x} d x = - \frac{1}{3} \int_{\frac{1}{11}}^{\frac{1}{5}} \frac{1}{x} d x$ $int_(1/11)^(1/5)-1/(3x)dx=-1/3int_(1/11)^(1/5)1/xdx$

$= \frac{1}{3} {[ln | x |]}_{\frac{1}{11}}^{\frac{1}{5}}$ $=1/3[ln|x|]_(1/11)^(1/5)$

$= \frac{1}{3} [ln (\frac{1}{5}) - ln (\frac{1}{11})]$ $=1/3[ln(1/5)-ln(1/11)]$

$= 0, 26282$ $=0,26282$

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How do you evaluate $\int (- \frac{1}{3 x}) d x$ $int (-1/(3x)) dx$ for [1/11, 1/5]?

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