How do you evaluate $int 1/750* (x+10)^4 *e^(-.07)$ for [0,125]?

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Answer 1 · 2015-09-27T17:27:54

Remove any constants from the integrand, then integrate.

$int_0^125(1/750)(x+10)^4e^-0.07dx$

$=(1/750)(e^-0.07)int_0^125(x+10)^4dx$

Now, integrate the polynomial with respect to x:

$=(1/750)(e^-0.07)(x+10)^5/5$

Finally, evaluate at the upper and lower limits [0,125]

$=[(1/750)(e^-0.07)(125+10)^5/5]$ - $[(1/750)(e^-0.07)(0+10)^5/5]$

#= 11,149,002

Hope that helped

How do you evaluate int 1/750* (x+10)^4 *e^(-.07) int 1/750* (x+10)^4 *e^(-.07) for [0,125]?