How do you evaluate $int abs(x)/10dx$ from -2 to 4?

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Answer 1 · 2016-07-12T09:58:52

1

$int_-2^4 abs(x)/10dx$

$int_-2^0 -x/10dx + int_0^4 x/10dx$

$[-x^2/20]_-2^0 + [x^2/20]_0^4$

= $1/5 + 4/5 = 1$

How do you evaluate int abs(x)/10dxint abs(x)/10dx from -2 to 4?