How do you evaluate $j (2 a)$ $j(2a)$ if $j (x) = 1 - 4 x^{3}$ $j(x)=1-4x^3$ ?

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How do you evaluate $j (2 a)$ $j(2a)$ if $j (x) = 1 - 4 x^{3}$ $j(x)=1-4x^3$ ?

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Answer 1 · 2016-11-11T21:32:55

$j (2 a) = - 32 a^{3} + 1$ $j(2a)=-32a^3+1$

Explanation:

Plug in $2 a$ $2a$ into the equation $j (x)$ $j(x)$ :

$j (2 a) = 1 - 4 {(2 a)}^{3}$ $j(2a) = 1-4(2a)^3$
$= 1 - 4 (8 a^{3})$ $=1-4(8a^3)$
$= 1 - 32 a^{3}$ $=1-32a^3$

Answer 2 · 2016-11-11T21:33:53

$j (2 a) = 1 - 32 a^{3}$ $j(2a)=1-32a^3$

Explanation:

If $j (x) = 1 - 4 x^{3}$ $j(color(red)x)=1-4color(red)(x)^3$
then
$XXX j (2 a) = 1 - 4 \cdot {(2 a)}^{3}$ $color(white)("XXX")j(color(red)(2a))=1-4 * (color(red)(2a))^3$

$XXXX = 1 - 4 \cdot (8 a^{3})$ $color(white)("XXXX")= 1-4 * (8a^3)$

$XXXX = 1 - 32 a^{3}$ $color(white)("XXXX")=1-32a^3$

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How do you evaluate $j (2 a)$ $j(2a)$ if $j (x) = 1 - 4 x^{3}$ $j(x)=1-4x^3$ ?

2 Answers

Explanation:

Explanation:

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How do you evaluate j(2a)j(2a)j(2a) if j(x)=1-4x^3j(x)=1−4x3j(x)=1-4x^3?

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Explanation:

Explanation:

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How do you evaluate $j (2 a)$ $j(2a)$ if $j (x) = 1 - 4 x^{3}$ $j(x)=1-4x^3$ ?