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How do you evaluate $log_x(1/36)= -(2/3)$ ?

1 Answer

Mar 10, 2016

$x=216$

Explanation:

$x^(-2/3) =1/36$
$x^(-2/3) =6^-2$
$(x^(-2/3))^(-3/2) =(6^-2)^(-3/2)$
$x=6^3=216$

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