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How do you evaluate $\sqrt{b^{2} - 4 a c}$ $sqrt(b^2-4ac)$ for a=1, b=7, c=-3?

1 Answer

Jun 28, 2017

$\sqrt{61}$ $sqrt61$

Explanation:

$Delta=sqrt(b^2-4ac)=sqrt(7^2-4*1*(-3))=sqrt(49+12)=sqrt61$

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