How do you evaluate the definite integral $\int 2 e^{x} d x$ $int 2e^x dx$ from $[0, 1]$ $[0,1]$ ?

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Answer 1 · 2017-01-07T05:51:04

The answer is $= 2 (e - 1)$ $=2(e-1)$

We use $\int e^{x} d x = e^{x} + C$ $inte^xdx=e^x+C$

$e^{0} = 1$ $e^0=1$

Therefore,

$\int_{0}^{1} 2 e^{x} d x = {[2 e^{x}]}_{0}^{x}$ $int_0^1 2e^xdx=[2e^x]_0^1$

$= (2 e^{1} - 2 e^{0})$ $=(2e^1-2e^0)$

$= 2 e - 2$ $=2e-2$

$= 2 (e - 1)$ $=2(e-1)$

How do you evaluate the definite integral ∫2exdxint 2e^x dx from [0,1][0,1]?