How do you evaluate the definite integral ∫(−2x2+4x+2)dx from [0,3]?
1 Answer
Jun 24, 2017
Explanation:
integrate each term using the power rule
∙∫axndx=an+1xn+1;n≠−1
⇒∫30(−2x2+4x+2)dx
=[−23x3+2x2+2x]30
[F(x)]30=F(3)−F(0)
=(−23×33+2×32+2×3)−0
=6