How do you evaluate the definite integral (2x2+4x+2)dx from [0,3]?

1 Answer
Jun 24, 2017

6

Explanation:

integrate each term using the power rule

axndx=an+1xn+1;n1

30(2x2+4x+2)dx

=[23x3+2x2+2x]30

[F(x)]30=F(3)F(0)

=(23×33+2×32+2×3)0

=6