How do you evaluate the definite integral #int(-2x^2+4x+2)dx# from #[0,3]#?
1 Answer
Jun 24, 2017
Explanation:
#"integrate each term using the "color(blue)"power rule"#
#• intax^ndx=a/(n+1)x^(n+1) ;n!=-1#
#rArrint_0^3(-2x^2+4x+2)dx#
#=[-2/3x^3+2x^2+2x]_0^3#
#[F(x)]_0^3=F(3)-F(0)#
#=(-2/3xx3^3+2xx3^2+2xx3)-0#
#=6#
