How do you evaluate the definite integral int 2x+3 from [1,3]?

1 Answer
Aug 16, 2016

14

Explanation:

To evaluate int_1^3(2x+3)dx

integrate using the color(blue)"power rule"

color(orange)"Reminder " color(red)(|bar(ul(color(white)(a/a)color(black)(int(ax^n)dx=a/(n+1)x^(n+1))color(white)(a/a)|)))

rArrint_1^3(2x+3)dx=[x^2+3x]_1^3

now evaluate function at upper limit and subtract the evaluation at the lower limit.

rArr[x^2+3x]_1^3=(9+9)-(1+3)=18-4=14