How do you evaluate the definite integral #int (3/x^2-1)dx# from [1,2]?
1 Answer
Oct 27, 2016
I found:
Explanation:
Let us write our integral in a slight different way to make the integraton easier:
now we integrate using our usual rules of integration to get:
we didn't add the constant because we now apply the limits of integration
when
when
Subtract them:
so we get that: