How do you evaluate the definite integral $int (-3v+4)dv$ from [2,5]?

Question

3167 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-05-23T22:16:27

$-39/2$

$int_2^5(-3v+4)dv$

the antiderivative is $F(v)=-3/2v^2+4v$

simply evaluate $F(5)-F(2)$
$=-3/2(5)^2+4(5)+3/2(2)^2-4(2)$
$=-75/2+20+6-8$
$=-39/2$

How do you evaluate the definite integral int (-3v+4)dvint (-3v+4)dv from [2,5]?