How do you evaluate the definite integral $\int (6 x^{2}) d x$ $int (6x^2)dx$ from [0,7]?

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Answer 1 · 2016-12-16T01:18:56

686

$\int_{0}^{7} 6 x^{2} d x = {[6 \cdot \frac{x^{3}}{3}]}_{0}^{7}$ $int_0^7 6x^2 dx =[6*x^3/3]_0^7$

$= 2 \cdot 7^{3} - 0 = 2 \times 343$ $= 2*7^3 - 0 = 2xx343$

$= 686$ $=686$

How do you evaluate the definite integral int (6x^2)dx∫(6x2)dxint (6x^2)dx from [0,7]?