Question

How do you evaluate the definite integral `int dx/x` from `[1,e]`?

Answer 1

1

Explanation:

`int_1^e\frac{dx}{x}=int_1^e\frac{1}{x}dx`
and because
`int\frac1xdx=ln(x)+C`

you can evaluate the integral:
`(ln(e)+C)-(ln(1)+C)`
`ln(e)-ln(1)`
`1-0`
`1`