How do you evaluate the definite integral int (x+1)dx from [1,5]?
1 Answer
Oct 26, 2017
Explanation:
"integrate each term using the "color(blue)"power rule"
•color(white)(x)int(ax^n)=a/(n+1)x^(n+1)to(n!=-1)
rArrint_1^5(x+1)dx
=[1/2x^2+x]_1^5
=(25/2+5)-(1/2+1)
=16