How do you evaluate the definite integral $int (x-2) dx$ from [-1,0]?

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Answer 1 · 2017-05-26T22:28:36

$int_(-1)^0 (x-2)dx = - 5/2$

$int_(-1)^0 (x-2)dx = int_(-1)^0 (x-2)d(x-2)$

$int_(-1)^0 (x-2)dx = [(x-2)^2/2]_(-1)^0$

$int_(-1)^0 (x-2)dx = (0-2)^2/2 - ((-1)-2)^2/2$

$int_(-1)^0 (x-2)dx = 2 - 9/2$

$int_(-1)^0 (x-2)dx = - 5/2$

How do you evaluate the definite integral int (x-2) dxint (x-2) dx from [-1,0]?