How do you evaluate the definite integral $int x^3 dx$ from $[0,4]$ ?

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Answer 1 · 2017-02-09T10:44:47

The answer is $=64$

We need

$intx^ndx=x^(n+1)/(n+1)+C(n!=-1)$

Therefore,

$int_0^4x^3dx=[x^4/4]_0^4$

$=(4^4/4-0)$

$=4^3=64$

How do you evaluate the definite integral int x^3 dxint x^3 dx from [0,4][0,4]?