How do you evaluate the definite integral $int x+7x^2 dx$ from $[3,4]$ ?

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Answer 1 · 2016-08-09T16:20:29

$int _3^4 (x+7x^2)d x=89.8bar 3$

$int _3^4 (x+7x^2)d x=?$

$int _3^4 (x+7x^2)d x=|1/2 x^2+7/3 x^3|_3^4$

$int _3^4 (x+7x^2)d x=[1/2*4^2+7/3*4^3]-[1/2*3^2+7/3*3^3]$

$int _3^4 (x+7x^2)d x=[16/2+448/3]-[9/2+189/3]$

$int _3^4 (x+7x^2)d x=16/2-9/2+448/3-189/3$

$int _3^4 (x+7x^2)d x=7/2+259/3$

$int _3^4 (x+7x^2)d x=(21+518)/6$

$int _3^4 (x+7x^2)d x=539/6$

$int _3^4 (x+7x^2)d x=89.8bar 3$

How do you evaluate the definite integral int x+7x^2 dxint x+7x^2 dx from [3,4][3,4]?