How do you evaluate the expression $[(1/3)^-2]^3$ using the properties?

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Answer 1 · 2018-03-11T18:38:36

$3^6$

$[(1/3)^-2]^3$
$(1/3)^(-2 *3) = (1/3)^-6 = (1^1/3^1)^-6 = (1^1)^-6 / (3^1)^-6$
$= 1^-6 / 3^-6 = (1/1^6) / (1/3^6) = 1*3^6/1 = 3^6$

How do you evaluate the expression [(1/3)^-2]^3[(1/3)^-2]^3 using the properties?