How do you evaluate the indefinite integral $int (x^5)dx$ ?

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Answer 1 · 2016-12-14T17:48:47

The answer is $=x^6/6+C$

We use

$intx^ndx=x^(n+1)/(n+1)+C (n!=-1)$

$intx^5dx=x^6/6+C$

How do you evaluate the indefinite integral int (x^5)dxint (x^5)dx?