How do you evaluate the integral $int 1/(x^2+2x+1)dx$ from -1 to 0?

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Answer 1 · 2016-11-04T12:47:22

There is a problem as $x!=-1$

Let's factorise the denominator
$x^2+2x+1=(x+1)^2$
We use $intx^ndx=x^(n+1)/(n+1) (x!=-1)$
There is a problem as $x!=-1$

$int_-1^0dx/(x+1)^2=(-1/(x+1))_-1^0=-1+oo$

How do you evaluate the integral int 1/(x^2+2x+1)dxint 1/(x^2+2x+1)dx from -1 to 0?