How do you evaluate the integral $int dt/(tlnt)$ ?

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Answer 1 · 2017-01-14T10:24:44

The answer is $=ln(∣ln(t)∣)+C$

We do a substitution

Let $u=lnt$ , $=>$ , $du=dt/lnt$

Therefore,

$int(dt)/(tlnt)=int(du)/u=lnu$

$=ln(∣ln(t)∣)+C$

How do you evaluate the integral int dt/(tlnt)int dt/(tlnt)?