How do you evaluate the integral $int lnx/xdx$ ?

Question

2485 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-01-11T13:15:23

$int lnx/x dx = 1/2(lnx)^2+C$

We have that:

$d/(dx) (lnx) = 1/x$

so:

$int lnx/x dx = int lnx d(lnx) = 1/2(lnx)^2+C$

How do you evaluate the integral int lnx/xdxint lnx/xdx?