How do you evaluate the power ${(- 0.8)}^{2}$ $(-0.8)^2$ ?

Question

How do you evaluate the power ${(- 0.8)}^{2}$ $(-0.8)^2$ ?

1 Answer

Impact of this question

9097 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-10-19T03:54:10

Multiply $- 0.8 \times - 0.8$ $-0.8 xx -0.8$

The answer is + .64

Explanation:

The exponent $x^{2}$ $x^2$ means to multiply the x by itself. Or to multiply the number by itself

In this case the x = -0.8 so

$- 0.8 \times - 0.8$ $-0.8 xx -0.8$ = the evaluation of ${(- 0.8)}^{2}$ $(-0.8)^2$

$- \times - = +$ $- xx - = +$ so the answer is positive not negative.

$.8 \times .8$ $.8 xx .8$ = .64

so the answer is + .64

Another way of looking at the problem is to write it as a fraction.

$- \frac{8}{10} \times - \frac{8}{10}$ $- 8/10 xx - 8/10$ = $(- \times -) \times \frac{8 \times 8}{10 \times 10}$ $( - xx - ) xx ( 8 xx 8)/ (10xx10)$ This gives

$+ \frac{64}{100}$ $+ 64/100$ as a decimal this is + 0.64

Science

Math

Humanities

... and beyond

How do you evaluate the power ${(- 0.8)}^{2}$ $(-0.8)^2$ ?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you evaluate the power (−0.8)2(-0.8)^2?

1 Answer

Explanation:

Related questions

Impact of this question

How do you evaluate the power ${(- 0.8)}^{2}$ $(-0.8)^2$ ?